Отправлено Borladn C++ Bilder 5 Help 26 декабря 2002 г. 14:56 В ответ на: Это ошибка в компиляторе IAR или что? отправлено Peter K. 26 декабря 2002 г. 14:16

Here are the steps C++Builder uses to convert the operands in an arithmetic expression:

1. Any small integral types are converted as shown in Methods used in standard arithmetic conversions. After this, any two values associated with an operator are either int (including the long and unsigned modifiers), or they are of type double, float, or long double.
2. If either operand is of type long double, the other operand is converted to long double.
3. Otherwise, if either operand is of type double, the other operand is converted to double.

4. Otherwise, if either operand is of type float, the other operand is converted to float.
5. Otherwise, if either operand is of type unsigned long, the other operand is converted to unsigned long.
6. Otherwise, if either operand is of type long, then the other operand is converted to long.
7. Otherwise, if either operand is of type unsigned, then the other operand is converted to unsigned.
8. Otherwise, both operands are of type int.

The result of the expression is the same type as that of the two operands.